Solution

First data:
Vo = 60 m/s
Vt = 45 m/s
S = 100 m
From the initial data kita find the particle deceleration as follows :
Vt²= Vo² − 2aS
45² = 60² − 2a(100)
2025 = 3600 − 200 a
200 a = 3600 − 2025
a = 1575 /200 = 7,875 m/s²

Large deceleration is 7,875 m/s² (Why not negative ? Because of the initial calculation negative sign is entered into the formula , if you want the results of a negative for , use the equation (Vt² = Vo² + 2aS)
Next data:
Vo = 45 m/s
Vt = 0 m/s (hingga berhenti)
J:
Vt2 = Vo2 − 2aS
02 = 45² − 2(7,875)S
0 = 2025 − 15,75.S
15,75S = 2025
S = 2025/15,75 = 128,5 m